Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

The table below shows the estimated population of fish living in the local lake as determined by the local
environment council every 10 years between 1960 and 1990.
The equation y = 1500(.9) describes the curve of best fit for the fish population (y). Let z represent the
number of 10-year intervals since 1960.
Year Population
1960
1500
1970
1350
1980 1210
1990 1100
Using this equation, what is the approximate predicted population of fish living in the lake in the year 2020?
A) 980
B) 800
C) 770
D) 720

Sagot :

The approximate predicted population of fish living in the lake in the year 2020 is; B: 800

How to Calculate Estimate population from a Table?

We are told that the equation that describes the curve of best fit for the fish population (y) is;

y = 1500(0.9)^(z)

where z represent the

number of 10-year intervals since 1960.

The table started in the year 1960 and we want to find the population in the year 2020.
Number of years after 2020 is;

2020 - 1960 = 60 years

60 years is 6 decades

Thus;

y = 1500(0.9)⁶ = 797 ≈ 800

Read more about Population Estimate at; https://brainly.com/question/372299

#SPJ1

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.