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A balloon containing 0.500 mol ar at 0.00°c and 65.0 kpa pressure is expanded by adding more argon. formula: pv = nrt (r = 8.317 l•kpa/mol•k) what is the original volume of the gas? l

Sagot :

Oseni

The original volume of the gas would be 17.45 L.

Ideal gas equation

For an ideal gas:

  PV = nRT, where P = pressure, V= volume, n = number of moles, T=temperature, and R = constant = 8.317 l•kpa/mol•k

In this case, n = 0.500 mole, T = 273K, P = 65.0 kpa.

Thus:              V = nRT/P = 0.5 x 8.317 x 273/65 = 17.45 L

More on ideal gas can be found here: https://brainly.com/question/8711877

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