Answer:
The genotype of the Dad must be X^AY because that's the only possible genotype for a normal male.
The genotype of the mom must be X^AX^a because that's the only way to have a colorblind son while being a normal mom. The colorblind son gets a Y from his dad and X^a from his mom.
The genotype ratio among the children must be 25% heterozygous dominant, 50% homozygous dominant, and 25% heterozygous recessive.
The phenotype ratio among the children must be 75% normal and 25% colorblind.
