Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
The amount of oxygen in grams that reacted with 5.6 g of hydrogen to produce 41.4 g of water is 36.8 g
Balanced equation
2H₂ + O₂ —> 2H₂O
Molar mass of O₂ = 32 g/mole
Mass of O₂ from the balanced equation = 1 × 32 = 32 g
Molar mass of H₂O = 18 g/mole
Mass of H₂O from the balanced equation = 2 × 18 = 36 g
SUMMARY
From the balanced equation above,
36 g of H₂O was produced from 32 g of O₂
NOTE: O₂ is the limiting reactant
How to determine the mass of oxygen required
From the balanced equation above,
36 g of H₂O was produced from 32 g of O₂
Therefore,
41.4 g of H₂O will be produced from = (41.4 × 32) / 36 = 36.8 g of O₂
Thus, 36.8 g of O₂ reacted to produce 41.4 g of H₂O
Learn more about stoichiometry:
https://brainly.com/question/14735801
#SPJ1
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.