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5.6 grams of hydrogen react with some oxygen. 41.4 grams of water is the product. How much oxygen reacted (in grams)?

Sagot :

The amount of oxygen in grams that reacted with 5.6 g of hydrogen to produce 41.4 g of water is 36.8 g

Balanced equation

2H₂ + O₂ —> 2H₂O

Molar mass of O₂ = 32 g/mole

Mass of O₂ from the balanced equation = 1 × 32 = 32 g

Molar mass of H₂O = 18 g/mole

Mass of H₂O from the balanced equation = 2 × 18 = 36 g

SUMMARY

From the balanced equation above,

36 g of H₂O was produced from 32 g of O₂

NOTE: O₂ is the limiting reactant

How to determine the mass of oxygen required

From the balanced equation above,

36 g of H₂O was produced from 32 g of O₂

Therefore,

41.4 g of H₂O will be produced from = (41.4 × 32) / 36 = 36.8 g of O₂

Thus, 36.8 g of O₂ reacted to produce 41.4 g of H₂O

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