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Sagot :
The amount of oxygen in grams that reacted with 5.6 g of hydrogen to produce 41.4 g of water is 36.8 g
Balanced equation
2H₂ + O₂ —> 2H₂O
Molar mass of O₂ = 32 g/mole
Mass of O₂ from the balanced equation = 1 × 32 = 32 g
Molar mass of H₂O = 18 g/mole
Mass of H₂O from the balanced equation = 2 × 18 = 36 g
SUMMARY
From the balanced equation above,
36 g of H₂O was produced from 32 g of O₂
NOTE: O₂ is the limiting reactant
How to determine the mass of oxygen required
From the balanced equation above,
36 g of H₂O was produced from 32 g of O₂
Therefore,
41.4 g of H₂O will be produced from = (41.4 × 32) / 36 = 36.8 g of O₂
Thus, 36.8 g of O₂ reacted to produce 41.4 g of H₂O
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