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Sagot :
Using it's concept, it is found that the probability that the first student chosen is a senior and the second student chosen is a sophomore is given by:
[tex]p = \frac{11}{320}[/tex]
What is a probability?
A probability is given by the number of desired outcomes divided by the number of total outcomes.
Researching this problem on the internet, we have that there are:
31 juniors, 10 sophomores, 17 juniors, 22 seniors.
Then:
- Out of 31 + 10 + 17 + 22 = 80 students, 22 are seniors, hence the probability that the first student is a senior is given by [tex]p_1 = \frac{22}{80} = \frac{11}{40}[/tex].
- All students can be chosen again, hence the probability that the second student is a sophomore is given by [tex]p_2 = \frac{10}{80} = \frac{1}{8}[/tex].
The events are independent, hence the probability of both is given by:
[tex]p = p_1p_2 = \frac{11}{40} \times \frac{1}{8} = \frac{11}{320}[/tex]
More can be learned about probabilities at https://brainly.com/question/14398287
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