Answered

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A ball is thrown from an initial height of 2 feet with an initial upward velocity of 35ft/s. The ball's height h (in feet) after t seconds is given by the following.

Sagot :

The values for time is  1.361 and 0.828.

What is quadratic equation?

A quadratic equation is a second-order polynomial equation in a single variable x, ax²+bx+c=0. with a ≠ 0 .

Given: h=-16t²+35t+2

so if the height is going to be 20ft,

20 = 2+35t-16t²

16t²-35t18=0

Solve the above quadratic equation

x= -b±√b²-4ac/2a

a=16, b=-5, c=18

x=[-(-35)±√(-35)²-4*16*18]/2*16

x= [35±√73]/32

x= 35+√73/32  and x= 35-√73/32

x=1.361 and 0.828.

Hence, the values for time is  1.361 and 0.828.

Learn more about this concept here:

https://brainly.com/question/23933071

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