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Sagot :
The angle that the water surface make with the horizontal is 0.527°.
How to calculate the angles?
The water vapor moves at speed. Therefore,
v = 2πr/T = (2 × π × 0.120)/7.25
= 0.104m/s
Also, the top layer of water deals a downward force if gravity which will be:
= mv²/r = 0.104/0.12 = 0.0901
There, the angle will be:
= tan(0.0901/9.8)
= 0.527°
In this case, the angle that the water surface make with the horizontal is 0.527°.
Learn more about angles on:
brainly.com/question/25716982
#SPJ4
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