At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
The area of the lawn is 2.5 times greater than the area of the garden.
What is Heron's formula in math?
Heron's formula for finding the area of a triangle in terms of the lengths of its sides.
In symbols, if a, b, and c are the lengths of the sides: Area = √s(s - a)(s - b)(s - c) where s is half the perimeter, or (a + b + c)/2.
Given vertices W(-100,-70), X(-100,0),Y(0,0), and Z(-60,-70) of a backyard,
We have to find distances WX, XY, YZ, ZW and XZ:
1. WX= √(-100+100)²+(0+70)²
=√0+4900
=70
2. XY= √(0+100)²+(0-0)²
=100 units.
3. YZ= √(-60-0)²+(-70-0)²
=√3600+4900
= √8500= 10√85
4. ZW= √(-60+100)²+(-70+70)²
=√40²+0
=40 units
5. XZ= √(-60+100)²+(-70+0)²
=√40²+70²
=√6500=10√65
Then:
1. the area of WXZ
[tex]\sqrt{(70+40+10\sqrt{65}) /2 * ({70+40+10\sqrt{65}) /2 -70* {(70+40+10\sqrt{65}) /2 -40[/tex]*[tex]\sqrt{(70+40+10\sqrt{65}) /2 -10\sqrt{65}[/tex]
=1400 feet²
Area of XYZ= [tex]\sqrt{(100+10\sqrt{65}+10\sqrt{85}) /2 * (100+10\sqrt{65}+10\sqrt{85}) /2 -100* {(100+10\sqrt{85}+10\sqrt{65}) /2[/tex]-[tex]\sqrt{-10\sqrt{85}*(10+10\sqrt{85} +10\sqrt{65}) /2 -10\sqrt{65}[/tex]
=3500 feet²
Then, ar(WXZ)/ ar (XYZ)= 3500/1400=2.5 times.
Learn more about heron's formula here:
https://brainly.com/question/20934807
#SPJ1
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.
