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Sagot :
Using the t-distribution, it is found that the margin of error for the 95% confidence interval is of $336.
What is a t-distribution confidence interval?
The confidence interval is:
[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]
In which:
- [tex]\overline{x}[/tex] is the sample mean.
- t is the critical value.
- n is the sample size.
- s is the standard deviation for the sample.
The margin of error is given by:
[tex]M = t\frac{s}{\sqrt{n}}[/tex]
The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 69 - 1 = 68 df, is t = 1.9955.
The standard deviation and sample size are given, respectively, by:
s = 1400, n = 69.
Hence, the margin of error in dollars is given by:
[tex]M = t\frac{s}{\sqrt{n}}[/tex]
[tex]M = 1.9955\frac{1400}{\sqrt{69}}[/tex]
M = 336.
More can be learned about the t-distribution at https://brainly.com/question/16162795
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