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Use the points (0, 4) and (-2, 3) to find the slope of the line and give the equation of this line.​

Use The Points 0 4 And 2 3 To Find The Slope Of The Line And Give The Equation Of This Line class=

Sagot :

Answer:

Choice C:   [tex]m=\frac{1}{2}; y=\frac{1}{2} x+4[/tex]

Step-by-step explanation:

To find your slope do:

[tex]\frac{y^2-y^1}{x^2-x^1}[/tex]

[tex]\frac{3-4}{-2-0}=\frac{-1}{-2} =\frac{1}{2}[/tex]

that's how you get 1/2

4 is just the y-int.

The required equation of line passes through (0, 4) and (-2, 3),  has slope of m = 1/2 , is y = 1/2x + 4. Option C is correct.

What is the equation?

The equation is the values of two expressions that are equal.

What is the slope of the line?

The slope of the line is the tangent angle made by the line with horizontal. i.e. m =tanx where x in degrees.

The slope of the equation line passing through (0, 4) and (-2, 3)
[tex]m=\frac{y_2-y_1}{x_2-x_1} \\m = (3 - 4) / (-2-0)\\m = -1/-2\\m = 1/2[/tex]

Strand form of the equation of the line,
[tex]y-y_1 = m(x-x_1)[/tex]
Putting values in the standard form of the equation of the line.

y - 4 = 1/2 * (x - 0)
y = 1/2 * x + 4
[tex]y = \frac{1}{2} x + 4[/tex]

Thus, the required equation of line passes through (0, 4) and (-2, 3),  has slope of m = 1/2 , is y = 1/2x + 4. Option C is correct.

Learn more about slopes here:
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