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Sagot :
The remainder of (h4 h2 – 2) ÷ (h 3). The remainder is 88.
Remainder
Given:
(h⁴ + h² – 2) ÷ (h + 3)
Using reminder theorem
First step is to equate:
h + 3 =0
h = - 3
Second step is to determine the remainder
Substitute h = - 3 into (h⁴ + h² – 2)
Hence:
h⁴ + h² – 2 = (-3)⁴ + (-3)² - 2
h⁴ + h² – 2= 81 + 9 - 2
h⁴ + h² – 2=90-2
h⁴ + h² – 2= 88 remainder
Therefore the remainder is 88.
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