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Sagot :
The sum of the first 28 terms in the sequence is 5600
Sum of sequence
The sum of sequences are known as series. Given the following
a₁ = 92
a₁ = ai-1 - 8
For the second term
a2 = a1 - 8
a2 = 92 - 8
a2 = 84
Determine the sum of first 28th terms
S28 = 28/2[2(92)+(28-1)(8)]
S28 = 14(184+27(8))
S28 = 14(400)
S28 = 5600
Hence the sum of the first 28 terms in the sequence is 5600
Learn more on sequence here: https://brainly.com/question/6561461
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Answer:
-448
Step-by-step explanation:
The sum of 28 terms of the arithmetic sequence with first term 92 and common difference -8 can be found using the formula for the sum of an arithmetic series.
Sn = (2a1 +d(n -1))(n/2) . . . . sum of n terms with first term a1, difference d
__
series sum
Using the above formula with a1=92, d=-8, and n=28, the sum is ...
S28 = (2·92 -8(28 -1))/(28/2) = (184 -216)(14) = -448
The sum of the first 28 terms of the sequence is -448.
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