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A bag contains​ pennies, nickels,​ dimes, and quarters. There are 50 coins in all. Of the​ coins, 16% are pennies and 34% are dimes. There are 3 more nickels than pennies. How much money does the bag​ contain?

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Answer:

  $5.83

Step-by-step explanation:

The total amount of money is the sum of the values of the various denomination coins.

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setup

Let p, n, d, q represent the numbers of pennies, nickels, dimes, and quarters, respectively.

  p + n + d + q = 50 . . . . . . there are 50 coins in all

  16% × 50 = p . . . . . . . . . . 16% are pennies

  34% × 50 = d . . . . . . . . . . 34% are dimes

  n = p +3 . . . . . . . . . . . . . . there are 3 more nickels than dimes

The total value is ...

  v = 0.01p +0.05n +0.10d + 0.25q

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solution

The numbers of pennies and dimes are found easily:

  0.16 × 50 = p = 8

  0.34 × 50 = d = 17

Then the number of nickels can be found:

  n = p +3 = 8 +3 = 11

Finally, the number of quarters is found from the total number of coins:

  p + n + d + q = 50

  8 + 11 + 17 + q = 50 . . . substitute known values

  q = 14 . . . . . . . . . . . . . subtract 36 from both sides

The total value is then ...

  v = 0.01(8) +0.05(11) +0.10(17) +0.25(14) = 0.08 +0.55 +1.70 +3.50

  v = 5.83

The bag contains $5.83.

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