Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
For part A, we will see that the distance is 7 units. For part B, the distance from Nina's house to the school to the grocery store is larger.
How to find the distances?
Remember that the distance between two points (a, b) and (c, d) is:
[tex]D = \sqrt{(a - c)^2 + (b - d)^2}[/tex]
A) Her house is at (-4, 10), and her school is at (-4, 3), so the distance is:
[tex]D = \sqrt{(-4 - (-4))^2 + (10 - 3)^2} = \sqrt{7^2} = 7[/tex]
The distance is 7 units.
B) In the first case, the distance between the school and the grocery store is:
[tex]D' = \sqrt{(-4 - (-4))^2 + (3 - (-6))^2} = 9[/tex]
So the total distance is 9 + 7 = 16
And the distance between the school and the community center is:
[tex]D'' = \sqrt{(-4 - 2)^2 + (3 - 3)^2} = 6[/tex]
So the total distance is 6 + 7 = 13
So we can see that the total distance from Nina's house, to the school, to the grocery store is larger than the other.
If you want to learn more about distance:
https://brainly.com/question/23848540
#SPJ1
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.