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Answer: The circles B and D are similar because B can be mapped onto D by a translation of 8 units to the right and 1 unit down, followed by a dilation about its center by a scale factor of 0.5.
All circles exist similar to each other. All points on the circumference of any circle exist equidistant from its center.
What is the similarity of a circle?
The similarity exists in the quality of scaling: two shapes stand equivalent if you can scale one to be like the other. All circles exist similar to each other.
All points on the circumference of any circle exist equidistant from its center. Because the size of any circle exists determined by its radius, we utilize the radii to define its scale factor.
Given that the circle B contains a radius = 4
circle D has a radius = 2
Now the scale factor exists given as :
[tex]$R_{D} * x = R_{B}[/tex]
Here the circle D exists even scaled to create a new circle of radius.
2 [tex]*[/tex] x = 4
X = 4/2 = 2
Here the radius of circle B exists two times scaled by circle B. Hence circle D and circle B exist similar.
Therefore, the correct answer is option D. The circles B and D are similar because B can be mapped onto D by a translation of 8 units to the right and 1 unit down, followed by a dilation about its center by a scale factor of 2.
To learn more about circles
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