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How much iodine (I2), in grams, should be added to water to produce 2.5L of solution with a molarity of 0.56M?

Sagot :

Molarity=Moles of solute/Volume of solution in L

So

  • 0.56M=moles/2.5L
  • moles=0.56(2.5)
  • moles of Iodine=1.4mol

Mads of Iodine

  • Moles(Molar mass)
  • 1.4(126.9)
  • 177.66g
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