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Find the slope of the line through the each pair of points
(16, 14), (-2, 0)

Sagot :

loneguy

Answer:

[tex]\text{Slope} = \dfrac{7}9[/tex]

Step-by-step explanation:

[tex]\text{Given that,}~ (x_1,y_1) = (16,14)~ \text{and}~ (x_2,y_2) = (-2,0)\\\\\text{Slope,}~ m = \dfrac{y_2 - y_1}{x_2 -x_1}\\\\\\~~~~~~~~~~~~=\dfrac{0-14}{-2-16}\\\\\\~~~~~~~~~~~~=\dfrac{-14}{-18}\\\\\\~~~~~~~~~~~~=\dfrac{7}9[/tex]

Itz5151

Answer:

m = 7/9

m = 7/9m ≈ 0.80

Step-by-step explanation:

Given two points:

(16, 14), (-2, 0)

To find:

The slope

Solution:

We know that,

[tex] \rm Slope(m) = \cfrac{ y_2 - y_1}{x_2 - x_1} [/tex]

According to the question,

  • y_2 = 0
  • y_1 = 14
  • x_2 = -2
  • x_1 = 16

Note:[The underscore refers to that the numbers after the underscore is a subscript]

So Substitute them on the formulae:

[tex] \implies \rm \: m = \cfrac{0 - 14}{ - 2 - 16} [/tex]

Simplify it.

[tex] \implies \rm \: m = \cfrac{ \cancel{- 14} \: {}^{7} }{ \cancel{- 18} \: {}^{9} } [/tex]

[tex] \implies \boxed{ \rm \: m = \cfrac{7}{9} }[/tex]

[tex] \implies \rm \boxed{ \rm m \approx0.80}[/tex]

Thus,the slope is 7/9 in fraction and 0.80 (Nearest tenth) in decimal.

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