The current equation of the perpendicular line;
⇒ is the slope-intercept form: [tex]y= mx + b[/tex]
- m: is the coefficient in front of the x, which is also the slope's value
- b: y-intercept of the function
Now for the point-slope form, we need a point on the line and the slope of the line:
⇒ we have
- slope = -3/2
- point: (-2,4)
Since this is the point-slope form: [tex](y-y_1)=m(x-x_1)[/tex]
⇒ where the (x₁,y₁) is the point on the line and m is the slope
[tex]= > Equation: (y-4)=-\frac{3}{2}(x+2)[/tex]
To convert the equation to slope-intercept form:
⇒ must isolate 'y' to one side and everything to the other side
[tex]y= -\frac{3}{2}(x+2)+4\\ y=-\frac{3}{2} x-3+4\\y=-\frac{3}{2}x+1[/tex]
Answer: [tex]y = -\frac{3}{2}x+1[/tex]
Hope that helps!
