Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Write the laws of refraction.(It should be Snell's law)​

Sagot :

Itz5151

Explanation:

Snell's Law of refraction:

Refraction of light obeys the following its two laws which's snell's law.

  • The incident ray, the normal at the point of incidence and the refracted ray, all lie in the same plane.
  • For a given pair of media and given colour of light, the ratio of the sine of angle of incidence i to the sine of angle of refraction r is a constant i.e.

[tex] \rm \cfrac{sin \: i}{sin \: r } = \mu[/tex]

This is known as the refractive index of the second medium with respect to the first medium. Mu is given as:

[tex] \rm\mu = \cfrac{Speed \; of \; light \; in\; the\; first \; medium}{Speed \; of \; light \; in\; the\; second \; medium}[/tex]

Let's take an example.

If a ray light travels from air to water,then mu = sin i/sin r is the refractive index of water with air.

[tex]\rm \cfrac{sin \: i}{sin \: r } = \mu[/tex]

Ex.1:Ray light from air to water

  • sin i = 3*10^6 m/s^1
  • sin r = 2.25*10^8 m s^-1

[tex] \rm \mu \: = \cfrac{3 \times {10}^{8} \: m \: s {}^{1} }{2.25 \times 10 {}^{8} \: m \: s {}^{ - 1} } = \cfrac{4}{3} = \boxed{ 1.33}[/tex]

Ex.2: Ray light from Air to glass:

  • sin i = 3*10^8 m s ^-1
  • sin r = 2*10^8 m s^-1

[tex] \rm \mu \: = \cfrac{3 \times {10}^{8} m \: s {}^{ - 1} }{2 \times {10}^{8 \: } m \: s {}^{ - 1} } = \cfrac{3}{2} = \boxed {1.5}[/tex]

[tex] \rule{225pt}{2pt}[/tex]

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.