Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Answer:
[tex]2\text{P}+ 5\text{Cl}_2 \rightarrow 2\text{PCl}_5[/tex]
Explanation:
Answer:
2P (s) + 5PCl₂ (g) → 2PCl₅ (s)
Explanation:
There are 2 chlorine atoms on the reactant side and 5 chlorine atoms on the product side.
Hence, multiply the left chlorine molecule by 5 and right compound by 2.
⇒ P (s) + 5 × Cl₂ (g) → 2 × PCl₅
⇒ P (s) + 5Cl₂ (g) → 2PCl₅ (s)
But, now we see that there is 1 phosphorus atom on the reactant side and 2 phosphorus atoms on the right.
So, multiply the left phosphorus atom by 2 to balance.
⇒ 2 × P (s) + 5PCl₂ (g) → 2PCl₅ (s)
⇒ 2P (s) + 5PCl₂ (g) → 2PCl₅ (s)
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.