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Balance the following chemical reaction :p(s) + cl2(g) = pcl5(s)

Sagot :

loneguy

Answer:

[tex]2\text{P}+ 5\text{Cl}_2 \rightarrow 2\text{PCl}_5[/tex]

Explanation:

Answer:

2P (s) + 5PCl₂ (g) → 2PCl₅ (s)

Explanation:

There are 2 chlorine atoms on the reactant side and 5 chlorine atoms on the product side.

Hence, multiply the left chlorine molecule by 5 and right compound by 2.

⇒ P (s) + 5 × Cl₂ (g) → 2 × PCl₅

⇒ P (s) + 5Cl₂ (g) → 2PCl₅ (s)

But, now we see that there is 1 phosphorus atom on the reactant side and 2 phosphorus atoms on the right.

So, multiply the left phosphorus atom by 2 to balance.

⇒ 2 × P (s) + 5PCl₂ (g) → 2PCl₅ (s)

⇒ 2P (s) + 5PCl₂ (g) → 2PCl₅ (s)

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