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Find the 14th term of the geometric sequence 5,-10,20

Sagot :

ItzFeelBeat

In this specific case, the initial term (a) is 5 and the common ratio (r) is -2

Henceforth, after determining what a and r are, we use the formula for the nth term. Which is:

[tex]a_n = a \times r^{n-1} [/tex]

Therefore, the 14th term is :

[tex]\implies 5 \times { (- 2)}^{14 - 1} \\\implies 5 \times {( - 2)}^{13} \\ =\boxed { -40,960} [/tex]

Hope it helps!

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