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Nina and Jo both ran a 13 km race.
Nina took 2 hour 10 minutes to run the whole race.
Jo started the race 7 minutes later than Nina but caught up when they had both travelled 11 km.
If Nina and Jo both ran at constant speeds, what is Jo's speed to 2 dp?

Sagot :

facundo3141592

We will see that Jo's speed, rounded to 2 digit places, is:

S =  6.42 km/h

How to get Jo's speed?

Remember that:

speed = distance/time.

Nina takes 2 hours and 10 minutes to finish the race, first, let's write the time in hours:

1 hour = 60 min.

Then:

10 min = (10/60) hours = 0.167 hours.

So we can write the time as:

2.167 hours.

And the distance is 13km, so her speed is:

S = 13km/2.167h = 6 km/h

The time that she takes to reach a distance of 11km (where she meets with Jo) is:

T = 11km/(6 km/h) = 1.83 hours.

Now, Jo starts 7 minutes after Nina, then the time in which he travels the 11 km is:

1.83 hours - 7 minutes.

Where:

7 min = (7min/60 min) hours = 0.117h

Then the time is:

T= 1.83h - 0.117h = 1.713 hours.

So he travels 11km in 1.713 hours, then his speed is:

S = 11km/ 1.713 hours = 6.42 km/h

If you want to learn more about speed:

https://brainly.com/question/4931057

#SPJ1

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