At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Answer:
(-3±√61)÷2
Step-by-step explanation:
First we expand the brackets to give us :
x²+5x-14 = -1 +2x
Now we make this into the quadratic format (x²+ax+b=0) by subtract -1 and 2x from both sides :
x²+3x-13 = 0
This quadratic cannot be factorized so we must use the quadratic formula :
x = [tex]\frac{-b+\sqrt{b^{2} -4ac} }{2a}[/tex] or x = [tex]\frac{-b-\sqrt{b^{2} -4ac} }{2a}[/tex]
a = 1 , b = 3 , c = -13
Now we simplify as much as possible by first substituting values known :
x = [tex]\frac{-3+\sqrt{3^{2} -4(1)(-13)} }{2(1)}[/tex] or x = [tex]\frac{-3-\sqrt{3^{2} -4(1)(-13)} }{2(1)}[/tex]
Now we evaluate the exponent :
x = [tex]\frac{-3+\sqrt{9 -4(1)(-13)} }{2(1)}[/tex] or x = [tex]\frac{-3-\sqrt{9 -4(1)(-13)} }{2(1)}[/tex]
Now we multiply the numbers :
x = [tex]\frac{-3+\sqrt{9 +52 } }{2(1)}[/tex] or x = [tex]\frac{-3-\sqrt{9 +52 } }{2(1)}[/tex]
Now we add the numbers :
x = [tex]\frac{-3+\sqrt{61} }{2(1)}[/tex] or x = [tex]\frac{-3-\sqrt{61} }{2(1)}[/tex]
Now we multiply the denominator:
x = [tex]\frac{-3+\sqrt{61} }{2}[/tex] or x = [tex]\frac{-3-\sqrt{61} }{2}[/tex]
So our final answer is (-3±√61)÷2
Hope this helped and 5 stars, a heart and brainliest please
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.
