Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
The molarity of a solution prepared by dissolving 3.11 grams of NaOH in
enough water to make 300 milliliters of solution is 0. 256 mol/ L
Explanation:
What is Molarity?
Molarity (M) is the amount of a substance in a given volume of solution. It is otherwise known as the number of moles of solute in a certain amount of solution.
The unit of molarity is mol/L
Formula for calculating molarity :
Molarity = number of moles of solute divided by the volume of the solution\
Parameters
Molarity = ?
Number of moles is calculated using :
Mass of the solute = 3.11 grams of NaOH
Molar mass of the solute = Na + O + H
Let's input the atomic numbers of the elements: Na (23) , O (16) , H (1)
Molar mass of NaOH = 23 + 16 + 1 = 40 g/ mol
Number of moles = 3.11 ÷ 40 = 0.077 mol
Volume of the solution is measured in Liters
Let's convert 300 milliters to liters = 300 divided by 1000 = 0.3 Liters
Molarity = 0.077 ÷ 0.3 = 0. 256 mol/ L
Therefore, the Molarity of the solution is 0. 256 mol/ L
Read more on molarity here :
https://brainly.com/question/26873446
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
