Answered

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Given the function h of x equals 8 times the cube root of x minus 6 end root plus 16, what is the x-intercept of the function?

–6
–2
2
16

Sagot :

MrRoyal

The x-intercept of the function [tex]h(x) = 8 * \sqrt[3]{x - 6} + 16[/tex] is -2

How to determine the x-intercept?

The equation of the function is given as:

[tex]h(x) = 8 * \sqrt[3]{x - 6} + 16[/tex]

The x intercept is the x value when h(x) = 0

So, we have:

[tex]8 * \sqrt[3]{x - 6} + 16 = 0[/tex]

Subtract 16 from both sides

[tex]8 * \sqrt[3]{x - 6} = -16[/tex]

Divide both sides by 8

[tex]\sqrt[3]{x - 6} = -2[/tex]

Take the cube of both sides

x - 6 = -8

Add 6 to both sides

x = -2

Hence, the x-intercept of the function [tex]h(x) = 8 * \sqrt[3]{x - 6} + 16[/tex] is -2

Read more about x-intercept at:

https://brainly.com/question/3951754

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