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what mass in grams of hydrogen is produced by the reaction of 4.73 g of magnesium with 1.83 of water

Sagot :

Oseni

The mass, in grams, of hydrogen that would be produced from the reaction will be 0.102 grams

Stoichiometric calculations

From the balanced equation of the reaction:

[tex]Mg + 2H_2O -- > Mg(OH)_2 + H_2[/tex]

The mole ration of magnesium to water is 1:2.

Mole of 4.73 grams Mg = 4.73/24.3 = 0.195 moles

Mole of 1.83 grams water = 1.83/18 = 0.102 moles

Hence, water is limiting.

Mole ratio of water to the hydrogen produced = 2:1

Equivalent mole of hydrogen gas produced = 0.102/2 = 0.05 moles

Mass of 0.05 moles hydrogen gas = 0.05 x 2 = 0.102 grams

More on stoichiometric calculations can be found here: https://brainly.com/question/27287858

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