Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Calculate the mass of water producd from the reaction of 126g of pentaboron noahydride with 192g of moleculAR OXYGEN

Sagot :

shimanekgare

Answer:

81.08g of H[tex]_{2}[/tex]O will be produced.

Explanation:

Write down the balanced chemical equation:

[tex]B_5H_9 + O_2[/tex] ⇒ [tex]B_2O_3+H_2O[/tex]

[tex]2B_5H_9+12O_2[/tex] ⇒ [tex]5B_2O_3+9H_2O[/tex]

Determine the limiting reagent:

[tex]B_5H_9[/tex] :-    126/63.12646 = 1.995993 mol

               1.995993/2 = 0.9979965

[tex]O_2[/tex] :-         192/31.9988 = 6.000225 mol

               6.000225/12 = 0.50001875

Therefore, [tex]O_2[/tex], is the limiting reagent.

Use stoichiometry ratios to determine the number of moles of water produced:

         [tex]O_2[/tex]         :        [tex]H_2O[/tex]

         12          :          9

  6.000225   :       4,500168756328362

Use the mole formula to calculate the mass of water produced:

[tex]n=\frac{m}{M} \\m=nM\\m=(4.500168756328362)(18.01528)\\m=81.08g[/tex]

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.