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Solve the rational equation:
2x 2x-5 -3 x-1 x²-3x+2 X-2
A. x= -0.47, X = -3.27 O
B. There is no solution.
C. X = -2, x = -1
D. x = 1, x = 2​


Solve The Rational Equation 2x 2x5 3 X1 X3x2 X2 A X 047 X 327 O B There Is No SolutionC X 2 X 1 D X 1 X 2 class=

Sagot :

The solution to the equation [tex]\frac{2x}{x - 1} - \frac{2x -5}{x^2 - 3x + 2} = \frac{-3}{x -2}[/tex] is (b) there is no solution.

How to solve the rational equation?

The equation is given as:

[tex]\frac{2x}{x - 1} - \frac{2x -5}{x^2 - 3x + 2} = \frac{-3}{x -2}[/tex]

Factorize the quadratic numerator

[tex]\frac{2x}{x - 1} - \frac{2x -5}{(x - 1)(x - 2)} = \frac{-3}{x -2}[/tex]

Multiply through by (x - 1)(x - 2)

2x(x - 2) - (2x -5) = -3(x - 1)

Expand

2x² - 4x - 2x + 5 = -3x + 3

Collect like terms

2x² - 4x - 2x + 3x + 5 - 3 = 0

Evaluate the like terms

2x² - 3x + 2 = 0

Using a graphical tool, the above equation has no real solution

Hence, the solution is (b) there is no solution.

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