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Calculate the ionization constant of each reaction. hcl (aq) + h2o (l) equation h3o+ (aq) + cl- (aq); [hcl] = 16.9m, [h3o+] = 13.3m, [cl-] = 7.4mka =

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The ionization constant from the reaction as shown in the calculation is 5.8.

What is the ionization constant?

The term ionization constant refers to the extent to which the acid is ionized in solution. It is calculated from;

Ka = [H3O^+] [Cl]/[HCl]

Thus when we substitute the values;

Ka = 13.3 * 7.4/ 16.9

Ka = 5.8

The ionization constant from the reaction as shown in the calculation is 5.8.

Learn more about ionization constant:https://brainly.com/question/13794673

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