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When a force of 450N pushes on a 20kg box as
shown, the acceleration of the box up the incline is
0.70m/s2. Find the coefficient of sliding friction
between the box and the incline.


Sagot :

Answer:

ma+mgsinh0​+f=F∴(25)(0.75)+(25)(10)sinh0​+μk​N=F∴18.75+(250)(0.6h)+μk​(mgcosh0​=F⟹18.75+150+μk​((25)(10)(0.76))=500∴168.75+μk​(190)=500⟹μk​(190)=331.25⟹μk​=1.74

Explanation: