Answered

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In ΔIJK, the measure of ∠K=90°, KJ = 11, IK = 60, and JI = 61. What is the value of the cosine of ∠J to the nearest hundredth?

Sagot :

The sine of ∠I is represented by the ratio 63:65

First, let's draw the triangle (see the picture below.)

We need to use it here.

What are trigonometric ratios?

-sin = opposite/hypotenuse

-cos = adjacent/hypotenuse

-tan = opposite/adjacent.

Assuming that ∠I is Ф,

we can see that its opposite side is equal to 63 and the hypotenuse is 65. Therefore,

[tex]sin(I)=\frac{63}{65} \\\\sinI=75^0[/tex]

To learn more about the trigonometric ratio visit:

https://brainly.com/question/24349828

#SPJ1

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