Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.


A fighter tank targets an enemy helicopter flying at an altitude of 1250 ft. If the ground
distance between the tank & the helicopter is 875 ft, what angle of elevation must the
cannon be raised to in order to hit the target?

Sagot :

facundo3141592

By using trigonometric relations, we will see that the angle of elevation must be 55°.

How to find the angle of elevation?

We can see this as a right triangle, where one cathetus measures 1250ft (altitude) and the other cathetus measures 875ft.

The angle of elevation is the angle such that the adjacent cathetus is the one measuring 875ft.

Then we can use the relation:

tan(a) = (opposite cathetus)/(adjacent cathetus)

tan(a) = 1250ft/875ft

To find the angle of elevation, we can use the inverse tangent function:

a = Atan(1250ft/875ft) = 55°

The angle of elevation must be 55 degrees.

If you want to learn more about right triangles:

https://brainly.com/question/2217700

#SPJ1

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.