Suppose that 5-ml containers of helium (He), neon (Ne), and argon (Ar) are at pressures of 1 atm,
2 atm, and 3 atm, respectively. The He and Ne are then added to the container of Ar.
a. What is the partial pressure of He in the container after the three gases are mixed?
b. What is the total pressure in the container after the three gases are mixed?

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03-06-2022
Chemistry

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Suppose that 5-ml containers of helium (He), neon (Ne), and argon (Ar) are at pressures of 1 atm,
2 atm, and 3 atm, respectively. The He and Ne are then added to the container of Ar.
a. What is the partial pressure of He in the container after the three gases are mixed?
b. What is the total pressure in the container after the three gases are mixed?

Sagot :

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ayoushivt ayoushivt · Answer 1 · 2022-06-14T06:45:12-04:00

The total pressure in the container after the three gases are mixed is 6 atm and the partial pressure of He is 1 atm.

What is Dalton's Law of Partial Pressure ?

According to Dalton's Law of Partial Pressure , the pressure exerted by a mixture of gas is equal to the sum of the partial pressure of the gases in the mixture.

P(total) = p₁ +p₂+p₃+.....

As the volume of the containers are same and the

n = 1*5/RT for Helium

n = 2*5 /RT for Neon

n= 3*5/RT for Argon

Mole fraction = moles of the element/Total moles

Moles fraction of Helium is

[tex]\rm \dfrac{1*5}{1*5+2*5+3*5}[/tex]

= 1/6

Total Pressure in the container = 1 + 2 +3 = 6 atm

The partial pressure of Helium will be

=Mole fraction * Total pressure

=(1/6)*6 atm

= 1 atm , as the volume is same the temperature is same , the pressure will also be same.

To know more about Dalton's Law

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Sagot :

What is Dalton's Law of Partial Pressure ?

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