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Please help me with this!​

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Sagot :

Answer:

Yes, x = 0 is a solution to the given equation

Step-by-step explanation:

  • [tex]1^3+1(1-1)=1-x^2[/tex] (Given)

  • [tex]L.H.S.=1^3+1(1-1)[/tex]

  • [tex]= 1 +1(0)[/tex]

  • [tex]= 1+0 [/tex]

  • [tex]=1[/tex]

  • [tex]R.H.S. =1-x^2[/tex]

  • [tex]=1-(0)^2[/tex] (Plug x = 0)

  • [tex]=1-0[/tex]

  • [tex]=1[/tex]

  • [tex]\implies L.H.S. = R.H.S.[/tex]

  • Thus, x = 0 is a solution to the equation [tex]1^3+1(1-1)=1-x^2[/tex]

Hi Student!

The goal of this question is to determine x = 0 is a solution of the expression that was provided.  The first step that we must take is input 0 into all of the x's that we have in the expression.  Then we just simplify both sides and determine if the end expression is true and if it is then x = 0 is a solution.

Plug in the values

  • [tex]1^3 + 1(1 - 1) = 1 - x^2[/tex]
  • [tex]1^3 + 1(1 - 1) = 1 - (0)^2[/tex]

Simplify both sides

  • [tex]1^3 + 1(0) = 1 - 0[/tex]
  • [tex]1 + 0 = 1[/tex]
  • [tex]1 = 1[/tex]

Looking at the final expression, we can see that 1 is indeed equal to 1 and since the expression is true, we can say that x = 0 is a solution of the expression that was provided in the problem statement.

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