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Sagot :
#21
- initial velocity=u=5m/s
- Time=t=2s
- Acceleration=a=1.3m/s²
According to first equation of kinematics
- v=u+at
- v=5+1.3(2)
- v=5+2.6
- v=7.6m/s
#22
#a
- v1=2+3(3)=2+9=11m/s
- v2=-8-4(3)=-20m/s
- v3=1-5(3)=-14m/s
The order is
- v2<V3<v1
#b
for speed find absolute velocity
- S1=|11|=11m/s
- S2=|-20|=20m/s
- S3=|-14|=14m/s
So order is
S1<S3<S2
Answer:
See below ~
Explanation:
Question 21 :
⇒ v = u + at
⇒ v = 5 + 1.3 (2)
⇒ v = 5 + 2.6
⇒ v = 7.6 m/s
=============================================================
Question 22 : At t = 3
Subpart (a)
⇒ Object 1 : v = 2 + 3(3) = 11 m/s
⇒ Object 2 : v = -8 - 4(3) = -20 m/s
⇒ Object 3 : v = 1 - 5(3) = -14 m/s
⇒ Hence, their velocities are in the order : Object 2 < Object 3 < Object 1
Subpart (b)
⇒ Object 1 : v = | 2 + 3(3) | = 11 m/s
⇒ Object 2 : v = | -8 - 4(3) | = 20 m/s
⇒ Object 3 : v = | 1 - 5(3) | = 14 m/s
⇒ Hence, their speeds are in the order : Object 1 < Object 3 < Object 2
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