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The heat of fusion for ice at 0°C is 333.7 kJ/kg, the specific heat of water 4.186 kJ/kg °C, and the heat of vaporization of water
at 100°C is 2,256 kJ/kg. What is the energy needed to vaporize 100 grams of ice at starting at 0°C?
Select one:
500 kJ

Sagot :

The energy needed to vaporize 100 grams of ice at starting at 0°C is  300.83 kJ.

What is heating?

When the temperature is increased , the body or particle is said to be heating.

Given is the mass of water =100g =0.1 kg, Latent heat of fusion L = 333.7 kJ/kg,

Energy required to melt ice into water at 0°C.

Q₁ = mL

Q₁ = 0.1 x 333.7

Q₁ = 33.37 kJ

Energy required to heat water from  0°C to 100°C is

Q₂ = mCΔT

Q₂ = 0.1 x 4.186 x 100

Q₂ = 41.86 J

Energy required to vaporize at 100°C is

Q₃ = m Lv

Q₃ = 0.1 x 2256

Q₃ = 225.6 kJ

Total heat to vaporize 100 grams of ice at starting at 0°C is

Q = Q₁ +Q₂ +Q₃

Q = 33.37 +41.86 +225.6

Q = 300.83 kJ

Thus, the energy needed to vaporize 100 grams of ice at starting at 0°C is  300.83 kJ

Learn more about heating.

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