The energy needed to vaporize 100 grams of ice at starting at 0°C is 300.83 kJ.
When the temperature is increased , the body or particle is said to be heating.
Given is the mass of water =100g =0.1 kg, Latent heat of fusion L = 333.7 kJ/kg,
Energy required to melt ice into water at 0°C.
Q₁ = mL
Q₁ = 0.1 x 333.7
Q₁ = 33.37 kJ
Energy required to heat water from 0°C to 100°C is
Q₂ = mCΔT
Q₂ = 0.1 x 4.186 x 100
Q₂ = 41.86 J
Energy required to vaporize at 100°C is
Q₃ = m Lv
Q₃ = 0.1 x 2256
Q₃ = 225.6 kJ
Total heat to vaporize 100 grams of ice at starting at 0°C is
Q = Q₁ +Q₂ +Q₃
Q = 33.37 +41.86 +225.6
Q = 300.83 kJ
Thus, the energy needed to vaporize 100 grams of ice at starting at 0°C is 300.83 kJ
Learn more about heating.
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