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Calculate the AH for the reaction C₂H4 (9) + H₂ (9)→ C₂H6 (g), from the following:
a. C₂H4 (g) + 3 O₂ (g) → 2 CO₂ (g) + 2 H₂O (1)
b. 2 C₂H6 (g) + 7 O₂ (g) → 4 CO₂ (g) + 6 H₂O (1)
c. 2 H₂ (g) + O₂ (g) → 2 H₂O (1)
AH = - 1411. KJ
AH = - 3120. KJ
AH = -571.6 kJ

Calculate The AH For The Reaction CH4 9 H 9 CH6 G From The Following A CH4 G 3 O G 2 CO G 2 HO 1 B 2 CH6 G 7 O G 4 CO G 6 HO 1 C 2 H G O G 2 HO 1 AH 1411 KJ AH class=

Sagot :

The AH for the reaction is -137 kJ

What is Enthalpy of Formation ?

Enthalpy of formation is the energy required by reactants to convert into products . It value can be positive or negative depending on the type of reaction, Endothermic or Exothermic.

In the question 3 step reaction is given

C₂H4 (g) + 3 O₂ (g) → 2 CO₂ (g) + 2 H₂O (1)   AH = - 1411. KJ

2 C₂H6 (g) + 7 O₂ (g) → 4 CO₂ (g) + 6 H₂O (1)   AH = - 3120. KJ

2 H₂ (g) + O₂ (g) → 2 H₂O (1)     AH = -571.6 kJ

To determine the enthalpy of formation for

C₂H4 (9) + H₂ (9)→ C₂H6 (g)

Adding reaction 1 and (1/2) 3 will give

C₂H4 (g) + 7/2 O₂ (g) + H₂ (g) ----> 2 CO₂ (g) + 3H₂O AH = -1696.8

For the second reaction

We will reverse the reaction and multiply it by 1/2

2 CO₂ (g) + 3 H₂O (1) -->  C₂H6 (g) + 7/2 O₂ (g)  AH = +1560

Adding the two new reactions.

C₂H4 (9) + H₂ (9)→ C₂H6 (g)    AH = -137 kJ

Therefore The AH for the reaction is -137 kJ

To know more about Enthalpy of Formation

https://brainly.com/question/14563374

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