Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Answer:
1093
Explanation:
Given expression:
- [tex]\sf \huge{ \sum _{n=0}^6\left(3\right)^n}[/tex]
Summation:
- [tex]\sf a_0+\sum _{n=1}^63^n[/tex]
Formula:
- [tex]\sf \sum\limits_{i=1}^n x_i = x_1 + x_2 + \dots + x_n[/tex]
Compute:
[tex]\rightarrow \sf 3^0 + 3^1 + 3^2 + 3^3 + 3^4 + 3^5 + 3^6[/tex]
[tex]\rightarrow \sf 1 + 3 + 9 + 27 + 81 + 243 + 729[/tex]
[tex]\rightarrow \sf 1093[/tex]
Answer:
[tex] \boxed{\rm \: SUM = 1093 }[/tex]
Step-by-step explanation:
Given:
[tex] \huge\rm {{ \sum}^6_{n=0\:} (3)^n}[/tex]
To Find:
Sum of the given finite series
Solution:
We'll use this formula:
[tex] \boxed{\rm SUM = a \cdot\bigg( \cfrac{1 - r {}^{n} }{1 - r} \bigg)}[/tex]
where,
- a = first term
- r = ratio in between terms
Let's find out the ratio R by using this formulae:
[tex] \rm \: r = \cfrac{a_{n + 1} }{a_n}[/tex]
According to the question,
- [tex]\rm a_n = 3^n[/tex]
- [tex]\rm a_{n+1}= 3^{n+1}[/tex]
Substitute:
[tex] \rm \: r = \cfrac{3 {}^{n + 1} }{3 {}^{n} } [/tex]
Apply law of exponents:[a^m/a^n] = a^m-n
[tex] \rm \: r = {3}^{n + 1 - n} [/tex]
Rearrange it as:
[tex] \rm \: r = 3 {}^{n - n + 1} [/tex]
[tex] \rm \: r = 3 {}^{1} = 3[/tex]
So,the ratio R is 3.
Now let's find out the First term A.
To find, substitute the value of n in 3^n:
- [It is given that n = 0]
[tex] \rm \: a = 3 {}^{0} [/tex]
- [x^0 = 1]
[tex] \rm \: a = 1[/tex]
Hence, first term A is 1.
NOW Substitute the value of the first term A and ratio R onto the formulae of sum:
[tex] \rm \: a \cdot\bigg( \cfrac{1 - r {}^{n} }{1 - r} \bigg)[/tex]
- a = 1
- r = 3
- n = 7
Simplify.
[tex] \rm SUM = \rm \: 1 \times \cfrac{1 - 3 {}^{7} }{ 1 - 1 \times 3} [/tex]
[tex] \rm \: SUM = \cfrac{ - 2186}{1 - 3} [/tex]
[tex] \rm \: SUM = \cfrac{ \cancel{ - 2186} \: \: {}^{1093} }{ \cancel{ - 2} \: \: ^{1} } [/tex]
[tex] \rm \: SUM = 1093[/tex]
We're done!
Hence, the sum of the given Finite series is 1093.
[tex] \rule{225pt}{2pt}[/tex]
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.