bunchmichelle04
Answered

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solve for x. x^2+12x<-11

Sagot :

199932

x²+12x<-11

x²+12x+11<0

x²+12x+11=0

(x+11)(x+1)=0

x+11=0 x+1=0

x= -11 x= -1

Solution: ] -11 , -1 [

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