Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.


(b) The graph display a load against extension plot for a metal wire of diameter 1.5 mm and original length
1m. When the load reached the value at a point A, the wire broke. From the graph deduce values of
i)force constant
ii)the youngs modulus for the metal of the wire


B The Graph Display A Load Against Extension Plot For A Metal Wire Of Diameter 15 Mm And Original Length 1m When The Load Reached The Value At A Point A The Wi class=

Sagot :

From Hooke's law, the force constant of the wire is 3.0 * 10^5 N/m while the Young Modulus is  6.4 * 10^7 .

What is Hookes law?

According to Hooke's law, the force is directly proportional to the extension of the wire.

Given that;

F = Ke

F = 240N

e = 0.8 mm or 0.0008m

K = F/e

K = 240N/0.0008m

K = 3.0 * 10^5 N/m

Now;

Young Modulus = 240N/(3.14 * (1.5 * 10^-3)^2)/0.0008m/1.5 * 10^-3

= 6.4 * 10^7

Learn more about force constant:https://brainly.com/question/15170479

#SPJ1

We appreciate your time. Please come back anytime for the latest information and answers to your questions. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.