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Solve ² + 12x = -20 by completing the square.

1. Add [b/2]² to bath sides of the equation. The value of [b/2]² in this equation is
A. 6
B. 10
C. 36 (CORRECT)
D. 100

2. Write the left side of the equation as a binomial squared. The left side of the equation becomes:
A. x+3
B. x+6 (CORRECT)
C. x+10
D. x+12

3. Use the square root property of equality.

4. Isolate the variable: x =
A. -4 or 4
B. -6 or 6
C. 2 or 10
D. -10 or -2 (CORRECT)​

I got it correct on Edge

Sagot :

1) Here, [tex]b=12[/tex], so [tex](b/2)^{2}=(12/2)^{2}=\boxed{36}[/tex]

2) If we add 36 to both sides, we get [tex]x^{2}+12x+36=16 \longrightarrow \boxed{(x+6)}^{2}=16[/tex]

3) If we take the square root of both sides,

[tex]x+6=\pm 4\\x=-10, -2[/tex]