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Sagot :
The molality of 35 g acetone dissolved in 0.95 kg water is 0. 63 mol/kg
How to determine the molality
Using the formula:
Molality = number of moles of solute÷ mass of solvent
Note that number of moles = mass divided by the molar mass
mass of acetone = 35g
Molar mass of acetone = 58. 1g/mol
Number of moles of acetone = 35÷ 58.1 = 0.602 mole
Molality of acetone = 0. 602÷ 0. 95 = 0. 63 mol/kg
Hence, the molality of acetone is 0. 63 mol/kg
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