Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Can someone help with number 4. I will reward brainliest.

Can Someone Help With Number 4 I Will Reward Brainliest class=

Sagot :

Answer:

theta = pi/6 and

theta = 5pi/6

Step-by-step explanation:

see image. Factor the expression. Solve for sin theta. Then use a calculator or unit circle to solve for theta. See image.

View image lpina68
linandrew41

Let's simplify the problem down a little:

 ⇒ set 'sin(θ)' as x

    ⇒ the new equation looks like: [tex]2x^2+5x-3=0[/tex]

Now let's solve this equation as a quadratic:

 [tex]2x^2+5x-3=0\\(2x-1)(x+3)=0\\\\2x-1=0\\x = \frac{1}{2} \\\\x+3 = 0\\x=-3[/tex]

Now set the x value of '1/2', to sin(θ)

  • it can't be -3, because trig functions can't equal a negative number

         sin(θ) = 1/2

            θ = π/6, which is between the range given

Answer: π/6

Hope that helps!

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.