playfulporpoise06
Answered

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What are the zeros of the quadratic function f(x) = 6x² - 24x + 1?

A.
[tex]x = - 2 + \sqrt{ \frac{1}{2} } or \: x = - 2 \: - \sqrt{ \frac{1}{2} } [/tex]
B.
[tex]x = 2 + \sqrt{ \frac{1}{2} } \: or \: x = 2 - \sqrt{ \frac{1}{2} } [/tex]
C.
[tex]x = - 2 + \sqrt{ \frac{23}{6} } \: or \: x = - 2 - \sqrt{ \frac{23}{6} } [/tex]
D.
[tex]x = 2 + \sqrt{ \frac{23}{6} } \: or \: x = 2 - \sqrt{ \frac{23}{6} } [/tex]
​

Sagot :

Answer:

D.

Step-by-step explanation:

Use Quadratic formula

x =  [-b +- sqrt (b^2 - 4ac) ]  / 2a     with a = 6   b = -24    c = 1

  to find

         x = 2 ± sqrt (23/6)

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