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What is the slope of the line that passes through the points (-6, 8) and (-9, 7)? Write your answer in simplest form.

Sagot :

Answer:

m=1/3

equation y=1/3x+10

Step-by-step explanation:

Find the rise and run.

1. -6--9=run=3

2. 8-7=rise=1

Hi student, let me help you out! :)

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We are asked to find the slope of the line that passes through (-6, 8) and (-9, 7).

[tex]\triangle~\fbox{\bf{KEY:}}[/tex] (formula for Slope)

[tex]\longmapsto\bf{\cfrac{y2-y1}{x2-x1}}[/tex]

y2 & y1 = the y-coordinates of the two points

x2 & x1 = the x-coordinates of the two points

[tex]\ddot\bigstar[/tex] Remember this...

[tex]\fbox{y2\;and\;y1\;are\;y-coordinates\;of\;the\;two\;points,\;and\;x2\;and\;x1\;are\;x-coordinates}}[/tex]

So we substitute the values and obtain:

[tex]\bf{\cfrac{7-8}{-9-(-6)}[/tex]

Simplifying:

[tex]\bf{\cfrac{-1}{-9+6}}[/tex]

Simplifying more:

[tex]\bf{\cfrac{-1}{-3}}[/tex]

Divide the top and bottom by -1:

[tex]\bf{\cfrac{1}{3}}[/tex]

There's the slope.

Hope it helps you out! :D

Ask in comments if any queries arise.

~Just a smiley person helping fellow students