The given quadratic equation [tex]y = x^2 + 3x - 10[/tex] Hence, the correct option is D one real root.
How to use discriminant to find the property of solutions of given quadratic equation?
Let the quadratic equation given be of the form ax^2 + bx + c = 0, then
The quantity [tex]b^2 - 4ac[/tex] is called its discriminant.
The solution contains the term [tex]\sqrt{b^2 - 4ac}[/tex] which will be:
Real and distinct if the discriminant is positive
Real and equal if the discriminant is 0
Non-real and distinct roots if the discriminant is negative
The given quadratic equation
[tex]y = x^2 + 3x - 10[/tex]
a = 1
b = 3
c = -10
The discriminant
[tex]b^2 - 4ac[/tex]
= 9 - 4(1)(-10)
= 9- 40
= - 31
Thus, Non-real and distinct roots if the discriminant is negative.
Hence, the correct option is D one real root.
Learn more about the discriminant of a quadratic equation here:
https://brainly.com/question/18659539
#SPJ1
