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A gas has a volume of 62.65 L at STP. At what temperature (in oC) would the volume of the gas be 78.31 L at a pressure of 612.0 mm Hg?

Sagot :

Answer:

1.788 C DEGREES

Explanation:

STP is 1 atm at  273.15 K

P1V1/T1  = P2V2/T2

(1)(62.65) / (273.15) = (612/760)(78.31)/T2

T2 = 274.93 K     = 1.788 C

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