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Determine the force p required to (a) raise and (b) lower the 40-kg cylinder at a slow, steady speed. the coefficient of friction between the cord and its supporting surface is 0.30.

Sagot :

Answer:

T - M g - Ff = M a     describes the acceleration of the object

T = M g + Ff      if the object moves at constant speed  (a = zero)

Ff = μ M g = .3 * 40 * 9.8 = 118 N     the force of friction

Ff will be in a direction opposite to the motion

M g = 40 kg * 9.8 m/s = 392 N

a) T = M g + Ff   for an object moving upwards

T = 392 + 118 = 510 N

b) T = M g - Ff     for an object moving downwards

T = 392 - 118 = 274 N