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Sagot :
The expression is assumed here as it's unclear looking
If it's P=(P_o)ln0.015t then the below solution of Part B is correct else they may vary.
#a
- 0.015 represents rate of change with respect to t.
#b
As per our assumed equation
It's.
- 8000=(P_o)ln0.015^t
Simplify
- tln0.015=8000/P_o
Initial amount of account is not given so you have to solve the above equation after putting known P_o
#3
- ln16
- ln4²
- 2ln4
- 2(1.38)
- 2.76(Approx)
Hence it's less than 3 and greater than 2
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