Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
334.22 grams of sodium chlorate and 91.56 grams of magnesium hydroxide would be produced respectively.
Stoichiometric calculation
From the equation of the reaction:
[tex]Mg(ClO_3)_2 + 2NaOH --- > 2NaClO_3 + Mg(OH)_2[/tex]
The mole ratio of magnesium chlorate to sodium hydroxide is 1:2.
With 2.72 moles of magnesium chlorate and 3.14 moles of sodium hydroxide provided respectively, the sodium hydroxide is limiting in availability.
Mole ratio of NaOH and [tex]NaClO_3[/tex] = 1:1
equivalent mole of [tex]NaClO_3[/tex] = 3.14 moles
Mass of 3.14 moles [tex]NaClO_3[/tex] = 3.14 x 106.44 = 334.22 grams
Mole ratio of NaOH and [tex]Mg(OH)_2[/tex] = 2:1
Equivalent mole of [tex]Mg(OH)_2[/tex] = 3.14/2 = 1.57 moles
Mass of 1.57 moles [tex]Mg(OH)_2[/tex] = 1.57 x 58.32 = 91.56 grams
More on stoichiometric calculations can be found here: https://brainly.com/question/27287858
#SPJ1
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.