Answered

Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Select the correct answer from each drop-down menu. a reaction proceeds with 2.72 moles of magnesium chlorate and 3.14 moles of sodium hydroxide. this is the equation of the reaction: mg(clo3)2 2naoh → mg(oh)2 2naclo3. determine the theoretical amount of each product that the reaction will produce. the reaction will produce of magnesium hydroxide and of sodium chlorate.

Sagot :

Oseni

334.22 grams of sodium chlorate and 91.56 grams of magnesium hydroxide would be produced respectively.

Stoichiometric calculation

From the equation of the reaction:

[tex]Mg(ClO_3)_2 + 2NaOH --- > 2NaClO_3 + Mg(OH)_2[/tex]

The mole ratio of magnesium chlorate to sodium hydroxide is 1:2.

With 2.72 moles of magnesium chlorate and 3.14 moles of sodium hydroxide provided respectively, the sodium hydroxide is limiting in availability.

Mole ratio of NaOH and [tex]NaClO_3[/tex] = 1:1

equivalent mole of  [tex]NaClO_3[/tex] = 3.14 moles

Mass of 3.14 moles  [tex]NaClO_3[/tex]  = 3.14 x 106.44 = 334.22 grams

Mole ratio of NaOH and [tex]Mg(OH)_2[/tex] = 2:1

Equivalent mole of  [tex]Mg(OH)_2[/tex] = 3.14/2 = 1.57 moles

Mass of 1.57 moles  [tex]Mg(OH)_2[/tex] = 1.57 x 58.32 = 91.56 grams

More on stoichiometric calculations can be found here: https://brainly.com/question/27287858

#SPJ1

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.